بسم الله الرحمن الرحيم
assumptions
i = sqrt(-1) -1
sqrt(ab) = sqrt(a)*sqrt(b)-2
proof
1+1 = 1+sqrt(1)
1 = -1*-1
then
1+1 = 1+sqrt(-1*-1)
from 2
1+1 = 1+ (sqrt(-1)*sqrt(-1))
1+1 = 1+(sqrt(-1))^2
1+1 = 1+-1
1+1 = 0
-----------------------
2+2=5
and this is the proof
let x=4 , y=5 ,z=1
then
z =y-x ; -> نضرب الطرفين * (y-x)
z(y-x)=(y-x)^2 ;
zy-zx=y2-2xy+x2 ; -> للطرفين -x2 نجمع
zy-zx-x2=y2-2xy ; ->للطرفين +xy نجمع
zy-zx-x2+xy=y2-xy ;-> للطرفين -zy نجمع
-zx-x2+xy=y2-xy-zy ;
x(-z-x+y)=y(y-x-z) ; -> /(y-x-z) نقسم الطرفين على
x=y;
but x=4 and y=5
then 4=5 !
now save math from being Collapsed
if you already know this give others chance to think
good luck
assumptions
i = sqrt(-1) -1
sqrt(ab) = sqrt(a)*sqrt(b)-2
proof
1+1 = 1+sqrt(1)
1 = -1*-1
then
1+1 = 1+sqrt(-1*-1)
from 2
1+1 = 1+ (sqrt(-1)*sqrt(-1))
1+1 = 1+(sqrt(-1))^2
1+1 = 1+-1
1+1 = 0
-----------------------
2+2=5
and this is the proof
let x=4 , y=5 ,z=1
then
z =y-x ; -> نضرب الطرفين * (y-x)
z(y-x)=(y-x)^2 ;
zy-zx=y2-2xy+x2 ; -> للطرفين -x2 نجمع
zy-zx-x2=y2-2xy ; ->للطرفين +xy نجمع
zy-zx-x2+xy=y2-xy ;-> للطرفين -zy نجمع
-zx-x2+xy=y2-xy-zy ;
x(-z-x+y)=y(y-x-z) ; -> /(y-x-z) نقسم الطرفين على
x=y;
but x=4 and y=5
then 4=5 !
now save math from being Collapsed

if you already know this give others chance to think
good luck
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